Determining Horizontal and Vertical Distance Traveled by a Baseball After 0.25 Seconds

To determine how far the baseball has traveled horizontally and how much it has fallen vertically after 0.25 seconds, we can use the equations of motion.

Given:

Initial horizontal velocity (u) = 20 m/s
Time

To find the horizontal distance traveled (x), we can use the equation:

x = u * t

Substituting the given values:

x = 20 m/s * 0.25 s = 5 meters

Therefore, the baseball has traveled 5 meters horizontally after 0.25 seconds.

To find the vertical distance fallen (y), we can use the equation for vertical motion under constant acceleration:

y = (1/2) * g * t^2

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the given values:

y = (1/2) * 9.8 m/s^2 * (0.25 s)^2 = 0.30625 meters

Therefore, the baseball has fallen approximately 0.30625 meters vertically after 0.25 seconds.

2023-10-19 15:08:01
#Solved #baseball #leaves #bat #horizontal #velocity #Matter #Energy

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